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The given diagram shows the steps in making a cross in Pea.
Statement I: A is Emasculation where the anthers are removed only after maturity.
Statement II: B is Pollination and it should be followed by bagging the flowers in the female parent.
(b)
Incorrect. Emasculation is the process of removing anthers before they mature to prevent self-pollination. Removing them after maturity would allow pollen release, defeating the purpose of emasculation.
A mother who is blood type AB has a child who is AB also. A potential father is blood type O. A well-informed
geneticist concludes that ______.
(a)
Blood group AB genotype = \( \mathbf{I}^{\mathrm{A}} \mathbf{I}^{\mathrm{B}} \)
Blood group O genotype = ii
Given:
Mother: Blood group AB → Genotype = \( \mathbf{I}^{\mathrm{A}} \mathbf{I}^{\mathrm{B}} \)
Child: Blood group AB → Genotype = \( \mathbf{I}^{\mathrm{A}} \mathbf{I}^{\mathrm{B}} \)
Potential Father: Blood group O → Genotype = ii
Can the father (ii) contribute to a child who is \(
\mathbf{I}^{\mathrm{A}} \mathbf{I}^{\mathrm{B}}
\) ?
No.
A person with ii (blood group O) can only pass ‘i’ alleles.
The child has \(
\mathrm{I}^{\mathrm{A}}
\) and \(
\mathrm{I}^{\mathrm{B}}
\), which must come from two \(
\mathrm{I}^{\mathrm{A}}
\) /\(
\mathrm{I}^{\mathrm{B}}
\) alleles, neither of which comes from the potential father with ‘i’ only.
Therefore,
✅ The O blood group male CANNOT be the father of an AB child.
Identify the incorrect statement regarding experiments on Pisum – sativum by Gregor Mendel.
(c)
Corrected Statement :- His experiments had a
large sampling size, which gave greater
credibility to the data that he collected
The figure shows a diagrammatic representation of a monohybrid cross.
If the conditions of the parental were to be different as given below, what would be the expected result of the cross?
(c)
Option 3 is correct if the genotypes of the parents remain the same (only the order is reversed).
In Mendel’s experiments, the contrasting traits did not show any blending in:
\(
\begin{array}{|l|l|}
\hline 1 . & F_1 \text { stage } \\
\hline 2 . & F_2 \text { stage } \\
\hline 3 . & \text { Both } F_1 \text { and } F_2 \text { stages } \\
\hline 4 . & \begin{array}{l}
\text { The statement is false as blending was seen at all } \\
\text { stages }
\end{array} \\
\hline
\end{array}
\)
(c)
Identify the incorrect statement :
(a)
A test cross is done to find out:
(b)
A test cross involves crossing an organism showing the dominant phenotype (but unknown genotype) with a homozygous recessive individual.
If the organism is homozygous dominant, all offspring will show the dominant trait.
If the organism is heterozygous, offspring will show a 1:1 ratio of dominant to recessive phenotypes.
So, a test cross helps determine whether the dominant phenotype is due to homozygous (pure) or heterozygous (hybrid) genotype
In a test cross, the plant expressing the dominant phenotype is crossed with the plant:
(c)
– Dominant phenotype may be due to homozygous dominant (AA) or heterozygous (Aa) genotype.
– Crossing with homozygous recessive (aa) reveals the hidden allele:
– If AA \( \times \) aa \( \rightarrow \) all Aa (dominant phenotype)
– If \( \mathrm{Aa} \times \mathrm{aa} \rightarrow 1 \mathrm{Aa}: 1 \mathrm{aa} \) ( \( 50 \% \) recessive offspring)
This helps determine the genotype of the dominant parent.
The figure shows the diagrammatic representation of a test cross. Based on the results shown, what would be true ?
\(
\begin{array}{|l|l|}
\hline \text { Statement I: } & \text { In situation A, the plant with the dominant phenotype [genotype unknown] must be homozygous dominant. } \\
\hline \text { Statement II: } & \text { In situation B, the plant with the dominant phenotype [genotype unknown] must be heterozygous. } \\
\hline
\end{array}
\)
(c)
What is the ratio of a typical monohybrid test cross ?
\(
\begin{array}{|l|l|l|l|}
\hline 1 . & 2: 1 & 2 . & 3: 1 \\
\hline 3 . & 1: 2: 1 & 4 . & 1: 1 \\
\hline
\end{array}
\)
(d)
\(
\begin{array}{|c|cc|c|}
\hline \text { Parent } & \text { Gametes } & \text { Progeny (Genotype : Phenotype) } \\
\hline \mathrm{Aa} \times \mathrm{aa} & A, a \text { and } \quad a & \begin{array}{l}
A \times a=A a \text { (Dominant) } \\
a \times a=a a \text { (Recessive) }
\end{array} \\
\hline
\end{array}
\)
Which of the following is not true for the Law of Dominance given by Mendel ?
(d)
The alleles do not show blending at the time of fertilization.
The expression of only one of the parental characters in a monohybrid cross in the \( F_1 \), the expression of both in the \( F_2 \) and the proportion of \( 3: 1 \) obtained at the \( F_2 \) can be explained by:
(a)
The law of segregation is based on the fact that :
(a)
The given figure shows meiosis and germ cell formation in a cell with four chromosomes and segregation when germ cells are formed. A and B would, respectively, be :
(b)
A heterozygous plant produces :
(b)
The inheritance of flower colour in dog flower and 4’O clock plant exhibits:
(b)
In the case of starch synthesis in pea seeds [controlled by the B gene], BB homozygotes produce large and round starch grains; bb homozygotes produce smaller and wrinkled starch grains and heterozygotes produce round seeds of intermediate size. What can be inferred from this observation ?
(c)
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A):
Dominance is not an autonomous feature of a gene or the product that it has information for.
Reason (R):
The frequency of a gene or an allele in a population is ultimately decided by
factors such as natural selection.
In the light of the above statements, choose the most appropriate answer from the options given below :
(b)
Does R explain A?
❌ No, it doesn’t.
Assertion (A) is about what determines dominance (i.e., gene product interactions inside an organism).
Reason (R) is about allele frequency in a population — a population-level concept, not directly explaining the molecular basis of dominance.
The figure shows the results of two dihybrid crosses conducted by Morgan where X and Y, respectively, are the percentages of parental and recombinants forms in Cross A and Cross B. Identify the correct statements :
Statement I: X will be parental types \( (98.7 \%) \) and recombinant types \( (1.3 \%) \); Y will be parental types \( (62.8 \%) \) and recombinant types (37.2%)
Statement II: The strength of linkage is inversely proportional to the distance between the genes located on the same chromosome.
(c)
When Mendel self-hybridized \( F_1 \) progeny of a dihybrid cross between pure Yellow Round seeded plants and Green Wrinkled plants, he observed that yellow and green colour segregated in a ratio of:
\(
\begin{array}{|l|l|l|l|}
\hline 1 . & 1: 1 & 2 . & 3: 1 \\
\hline 3 . & 9: 3: 3: 1 & 4 . & 1: 2: 1 \\
\hline
\end{array}
\)
(b)
Dihybrid Cross :
Mendel crossed :
Pure Yellow Round (YYRR) × Green Wrinkled (yyrr)
→ F₁: All Yellow Round (YyRr)
Then he self-hybridized the F₁ (YyRr × YyRr)
🟡 Yellow is dominant (Y)
🟢 Green is recessive (y)
So from Yy × Yy (F₁ self-cross for colour), the segregation ratio is:
𝑌𝑌 : 𝑌𝑦 : 𝑦𝑦 = 1: 2 : 1 ⇒
Phenotypically: Yellow : Green => 3:1
What is \( \mathrm{F}_2 \) phenotypic ratio in a dihybrid cross ?
\(
\begin{array}{|l|l|l|l|}
\hline 1 . & 1: 1 & 2 . & 3: 1 \\
\hline 3 . & 9: 3: 3: 1 & 4 . & 1: 1: 1: 1 \\
\hline
\end{array}
\)
(c)
When two pairs of traits are combined in a hybrid, segregation of one pair of characters is independent of the other pair of characters’. This is the statement of:
(c)
Mendel’s work remained unrecognised till 1900. Which of the following was not a reason for this ?
(a)
In 1900, Mendel’s work was rediscovered by :
(b)
The following figure shows the determination of sex by chromosomal differences. Which of the following is/are correctly matched ?
(a)
Depicted:
🔴 Labeling is incorrect in the image.
In birds:
But the symbols (♂ and ♀) are swapped in the diagram.
“Chromosomes, which are seen in all dividing cells and pass from one generation to the next, are the basis for all genetic inheritance”.
This statement is credited to:
(c)
The two alleles of a gene pair are located on :
(c)
T. H. Morgan worked on the fruit fly, Drosophila melanogaster. Which of the following is not an advantage of this fly ?
(b)
They complete their life
cycle in about two weeks, and a single mating could produce a large number of progeny flies.
Morgan coined the term ______ to describe this physical association of genes on a chromosome and the term _______ to describe the generation of nonparental gene combinations.
(d)
The figure shows the mechanism of sex determination in a honey bee. How many of the given statements will be true for the mechanism of sex determination in honey bees ?
I. The sex determination in honey bee is based on the number of sets of chromosomes an individual receives.
II. An offspring formed from the union of a sperm and an egg develops as a female (queen or worker), and an unfertilised egg develops as a male (drone) by means of parthenogenesis.
III. The males have double the number of chromosomes than that of a female, therefore, the females are haploid having 16 chromosomes and the males are diploid, i.e., having 32 chromosomes.
IV. This is called a haplodiploid sex-determination system.
V. The males produce sperms by mitosis, they do not have a father and thus cannot have sons, but have a grandfather and can have grandsons.
(c)
Total 4 statements are correct
The males have double the number of chromosomes than that of a female, therefore, the females are haploid having 16 chromosomes and the males are diploid, i.e., having 32 chromosomes.
❌ False — This statement reverses the facts:
Females are diploid (32 chromosomes)
Males are haploid (16 chromosomes)
➡️ So, it should say females have double the number of chromosomes compared to males.
Genes tightly linked on the same chromosome show:
(c)
Morgan, in his experiment on fruit flies, found that the genes white and yellow were very tightly linked and showed :
(d)
A dihybrid test cross results in a recombination frequency of \( 50 \% \). Most likely the two genes under consideration:
(b)
A trait displays continuous phenotypic variation and is spread across a gradient. Usually, the inheritance of this trait can be described as :
(c)
Identify Incorrectly Matched Pair:-
(d)
Diamond with a number does not indicate affected status.
It simply shows number of offspring of unspecified sex.
Affected individuals must be shown separately with filled symbols (⬛◼️).
So, saying “five affected offspring” using a diamond is misleading or wrong.
Human skin colour is a polygenic trait controlled by :
(b)
Identify the number of correct statements:
I. Polygenic inheritance takes into account the influence of the environment
II. In a polygenic trait the phenotype reflects the contribution of each allele, i.e., the effect of each allele is additive.
III. The normal distribution curve is bell-shaped in polygenic inheritance.
IV. It is also known as quantitative inheritance.
(d)
All are Correct
The mode of inheritance of the Mendelian disorder shown in the given pedigree chart is most likely:
(b)
Autosomal recessive ❌
Would skip generations and often appear in siblings, not parents/children — not seen here.
Sex-linked recessive ❌
Would mostly affect males, and affected females would be very rare — not matching this chart.
Sex-linked dominant ❌
Affected fathers would pass the trait to all daughters but no sons, which is not consistent here.
\(
\begin{array}{|c|l|l|}
\hline
\textbf{Column A} & \textbf{Column B} \\
\hline
\text{I. Chromosomal aberration} & \text{A. An additional sex chromosome} \\
\text{II. Down’s syndrome} & \text{B. Inversion} \\
\text{III. Klinefelter’s syndrome} & \text{C. Presence of an extra chromosome} \\
\text{IV. Turner’s syndrome} & \text{D. Absence of sex chromosome} \\
\hline
\end{array}
\)
The correct match is :-
(c)
Occasionally, a single gene may express more than one effect. The phenomenon is called :
(c)
The mode of inheritance of the Mendelian disorder shown in the given pedigree chart is most likely :
(a)
❌ Option 2: Autosomal dominant
In dominant inheritance, an affected person must have at least one affected parent.
But in the pedigree, unaffected parents (unshaded) have affected children → Not possible with dominant inheritance.
Also, the trait skips generations, which dominant traits usually do not.
❌ Option 3: Sex-linked recessive
In sex-linked recessive disorders (usually X-linked), males are more affected than females.
Here, both males and females are affected fairly equally, so not sex-linked.
Also, affected females would pass it to all sons, which is not consistently seen.
❌ Option 4: Sex-linked dominant
In X-linked dominant:
Affected fathers would pass the trait to all daughters, but no sons.
This pattern is not seen in the chart.
Also, both males and females are affected in a pattern that doesn’t fit X-linked dominance.
The physiological basis of pleiotropy is :
(d)
Lack of independent assortment in linked genes → describes linkage, not pleiotropy
Separation of homologous at Anaphase I → relates to meiosis, not gene expression
Dominance is not autonomous → describes dominance, not pleiotropy
Consider the given statements :
I: Where a single gene can exhibit multiple phenotypic expressions, such a gene is called a pleiotropic gene.
II: The underlying mechanism of pleiotropy in most cases is the effect of a gene on metabolic pathways which contribute towards different phenotypes.
Phenylketonuria is caused by a defect in the gene that codes for the enzyme phenylalanine
III: hydroxylase and manifests itself through phenotypic expression characterised by mental retardation and a reduction in hair and skin pigmentation.
(d)
The figure shows the point mutation responsible for the pathogenesis of sickle cell anaemia. Identify the correct statements.
Statement I: The peptide chain of the haemoglobin molecule that gets mutated leading to the disease is the alpha chain.
Statement II: The mRNA codon X can be GAG and the mRNA codon Y can be GUG.
(b)
A couple has a daughter. What is the probability that their next child will be a daughter ?
\(
\begin{array}{|l|l|l|l|}
\hline 1 . & 0 \% & 2 . & 25 \% \\
\hline 3 . & 50 \% & 4 . & 100 \% \\
\hline
\end{array}
\)
(c)
Always half percentage rather it is first or whatever child answer always half of the percentage
It is unfortunate that in our society women are blamed for producing female children and have been ostracised and ill-treated because :
Study the given figures and select the correct statements:-
\(
\begin{array}{|l|l|}
\hline \text { Statement I: } & \text { Part A shows the common clinical features of Down’s syndrome. } \\
\hline \text { Statement II: } & \text { Part B shows the characteristic karyotype of Down’s Syndrome. } \\
\hline
\end{array}
\)
(a)
Part B shows a karyotype (chromosome analysis). Notice chromosome 18 is trisomic (three copies), which is circled.
❌ This is characteristic of Edwards Syndrome (Trisomy 18), not Down’s Syndrome, which is caused by Trisomy 21 (three copies of chromosome 21).
So, Statement II is incorrect.
In birds, the mechanism of sex determination is :
(b)
Consider the following Statements :-
\(
\begin{array}{|l|l|}
\hline \text { I. } & \begin{array}{l}
\text { People affected by phenylketonuria are unable to } \\
\text { convert tyrosine to phenylalanine. }
\end{array} \\
\hline \text { II. } & \begin{array}{l}
\text { Alzheimer’s disease results from the accumulation of } \\
\text { amyloid protein plaques in the brain. }
\end{array} \\
\hline \text { III. } & \begin{array}{l}
\text { Klinefelter’s and Turner’s syndromes are the result of } \\
\text { nondisjunction of the sex chromosomes in either of } \\
\text { the sexes. }
\end{array} \\
\hline
\end{array}
\)
Which of the above statements are true ?
(c)
I:- ❌ Incorrect
Actually, phenylketonuria (PKU) is caused by a mutation in the gene coding for the enzyme phenylalanine hydroxylase.
This enzyme converts phenylalanine → tyrosine (not the other way around).
In PKU, phenylalanine accumulates and gets converted into harmful substances like phenylpyruvate.
✅ Correct: People with PKU can’t convert phenylalanine to tyrosine.
During his observation of spermatogenesis in a few insects, Henking found that a nuclear structure was received by \( 50 \% \) of the sperms. He called this structure as:
(a)
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