Significant Figures
Every measurement involves errors. Thus, the result of measurement should be reported in a way that indicates the precision of measurement. Normally, the reported result of measurement is a number that includes all digits in the
number that are known reliably plus the first digit that is uncertain. The reliable digits plus the first uncertain digit are known as significant digits or significant figures. If we say the period of oscillation of a simple pendulum is 1.62 s, the digits 1 and 6 are reliable and certain, while the digit 2 is uncertain. Thus, the measured value has three significant figures. The length of an object reported after measurement to be 287.5 cm has four significant figures, the digits 2, 8, and 7 are certain while the digit 5 is uncertain.
Example 1:
Each side of a cube is measured to be \(7.203 \mathrm{~m}\). What are the total surface area and the volume of the cube to appropriate significant figures?
Answer: The number of significant figures in the measured length is 4. The calculated area and the volume should therefore be rounded off to 4 significant figures.
Surface area of the cube \(=6(7.203)^{2} \mathrm{~m}^{2}\) \(=311.299254 \mathrm{~m}^{2}\) \(=311.3 \mathrm{~m}^{2}\)
Volume of the cube
\(=(7.203)^{3} \mathrm{~m}^{3}\)
\(=373.714754 \mathrm{~m}^{3}\)
\(=373.7 \mathrm{~m}^{3}\)
Example 2:
\(5.74 \mathrm{~g}\) of a substance occupies \(1.2 \mathrm{~cm}^{3}\). Express its density by keeping the significant figures in view.
Answer: There are 3 significant figures in the measured mass whereas there are only 2 significant figures in the measured volume. Hence the density should be expressed to only 2 significant figures.
\(
\begin{aligned}
\text { Density } &=\frac{5.74}{1.2} \mathrm{~g} \mathrm{~cm}^{-3} \\
&=4.8 \mathrm{~g} \mathrm{~cm}^{-3}
\end{aligned}
\)
Example 3: Round off the following numbers to three significant digits (a) 15462, (b) \(14 \cdot 745\), (c) \(14 \cdot 750\) and (d) \(14 \cdot 650\) \(\times 10^{12}\)
Answer: (a) The third significant digit is 4. This digit is to be rounded. The digit next to it is 6 which is greater than 5. The third digit should, therefore, be increased by 1. The digits to be dropped should be replaced by zeros because they appear to the left of the decimal. Thus, 15462 becomes 15500 on rounding to three significant digits.
(b) The third significant digit in \(14 \cdot 745\) is 7. The number next to it is less than 5. So \(14 \cdot 745\) becomes \(14 \cdot 7\) on rounding to three significant digits.
(c) 14.750 will become 14.8 because the digit to be rounded is odd and the digit next to it is 5.
(d) \(14.650 \times 10^{12}\) will become \(14.6 \times 10^{12}\) because the digit to be rounded is even and the digit next to it is 5.
Example 4: Evaluate \(\frac{25 \cdot 2 \times 1374}{33.3}\). All the digits in this expression are significant.
Answer: We have \(\frac{25 \cdot 2 \times 1374}{33 \cdot 3}=1039 \cdot 7838 \ldots\)
Out of the three numbers given in the expression \(25^{\circ} 2\) and 33.3 have 3 significant digits and 1374 has four. The answer should have three significant digits. Rounding \(1039 \cdot 7838 \ldots\) to three significant digits, it becomes 1040. Thus, we write
\(
\frac{25 \cdot 2 \times 1374}{33 \cdot 3}=1040 \text {. }
\)
Example 5: \(\text { Evaluate } \quad 24 \cdot 36+0 \cdot 0623+256 \cdot 2 \text {. }\)
Answer:
\(
\begin{gathered}
24 \cdot 36 \\
0.0623 \\
256 \cdot 2 \\
\hline
\end{gathered}
\)
Now the first column where a doubtful digit occurs is the one just next to the decimal point (2562). All digits right to this column must be dropped after proper rounding. The table is rewritten and added below
\(
\begin{array}{r}
24 \cdot 4 \\
0 \cdot 1 \\
256 \cdot 2 \\
\hline 280 \cdot 7
\end{array}
\)
The sum is \(280 \cdot 7\).
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