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The value of \(x\) which makes the following statement true is \(\left(3 \frac{7}{11} \times \frac{11}{5}\right) \div\left(\frac{3}{7} \times x\right)=\frac{4}{3}\) [JNV 2015]
Simplification of the following gives \(15 \frac{1}{2}-\left[\frac{12}{5} \times \frac{5}{8}+\left(7 \div 1 \frac{3}{4}\right)\right] \times 2\) [JNV 2019]
A man buys a TV at Rs.18200. He spends Rs. 1800 on repairing of TV. If he wants Rs. 3000 as profit. What is the selling price of TV? [JNV 2018]
Total cost price of TV = Rs. 18200 + Rs. 1800 = Rs. 20000; Profit = Rs. 3000 (given)
We know that, Selling price = Cost price + Profit = Rs. 20000 + Rs. 3000 = Rs. 23000
Kaku got 7 marks less than Bakshi while Raman got 3 marks more than Kaku. If the total marks obtained by all three is 76. Find the marks obtained by Raman. [JNV 2018]
Let marks obtained by Kaku = x
Marks obtained by Raman = x + 3
Marks obtained by Bakshi = x + 7
According to the question x + x + 3 + x + 7 = 76; x = 22.
Therefore, Marks obtains by Raman = x = 3 = 25
The average of 20 values is 18. If 3 is subtracted from each of the values, then the new average will be [JNV 2017]
Previous total = 20 × 18 = 360
New case = 360 – 3 × 20 = 300
Therefore, New average = 300 ÷ 20 = 15
Two numbers are in the ratio 2:3. If 9 is added to each, they will be in the ratio 3:4, the numbers are [JNV 2017]
Unit digit of the product of the first ten prime numbers is [JNV 2014]
The product of the three numbers is 7980. In which the product of two numbers is 228, then what is the third number? [JNV 2007]
The number 13013 is divisible by 13. The smallest 5 digit number beginning with 14 and exactly divisible by 13 is [JNV 2003, 1995]
The product of the two numbers is 8192. One of the numbers is two times the second number, the smaller number is [JNV 2004]
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