0 of 10 Questions completed
Questions:
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading…
You must sign in or sign up to start the quiz.
You must first complete the following:
0 of 10 Questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 point(s), (0)
Earned Point(s): 0 of 0, (0)
0 Essay(s) Pending (Possible Point(s): 0)
\(
7-24 \div 8 \times 4+6=?
\)
\(
\begin{aligned}
&7-24 \div 8 \times 4+6 \\
&=7-3 \times 4+6 \\
&=7-12+6 \\
&=-5+6 \\
&=1 \checkmark
\end{aligned}
\)
\(
18 \div 3-7+2 \times 5=?
\)
\(
\begin{aligned}
&18 \div 3-7+2 \times 5 \\
&=6-7+2 \times 5 \\
&=6-7+10 \\
&=-1+10 \\
&=9
\end{aligned}
\)
\(
6 \times 4 \div 12+72 \div 8-9=?
\)
\(
\begin{aligned}
&6 \times 4 \div 12+72 \div 8-9 \\
&=24 \div 12+72 \div 8-9 \\
&=2+72 \div 8-9 \\
&=2+9-9 \\
&=11-9 \\
&=2
\end{aligned}
\)
\(
(17-6 \div 2)+4 \times 3=?
\)
\(
\begin{aligned}
&(17-6 \div 2)+4 \times 3 \\
&=(17-3)+4 \times 3 \\
&=(14)+4 \times 3 \\
&=14+12 \\
&=26
\end{aligned}
\)
\(
-2(1 \times 4-2 \div 2)+(6+2-3)=?
\)
\(
\begin{aligned}
&-2(1 \times 4-2 \div 2)+(6+2-3) \\
&=-2(4-1)+(6+2-3) \\
&=-2(3)+(6+2-3) \\
&=-2(3)+(8-3) \\
&=-2(3)+(5) \\
&=-6+5 \\
&=-1
\end{aligned}
\)
\(
-1 \times[(3-4 \times 7) \div 5]-2 \times 24 \div 6=?
\)
\(
\begin{aligned}
&-1 \times[(3-4 \times 7) \div 5]-2 \times 24 \div 6 \\
&=-1 \times[(3-28) \div 5]-2 \times 24 \div 6 \\
&=-1 \times[(-25) \div 5]-2 \times 24 \div 6 \\
&=-1 \times[-5]-2 \times 24 \div 6 \\
&=5-2 \times 24 \div 6 \\
&=5-48 \div 6 \\
&=5-48 \div 6 \\
&=5-8 \\
&=-3
\end{aligned}
\)
\(
\left(3 \times 5^2 \div 15\right)-\left(5-2^2\right)=?
\)
\(
\begin{aligned}
&\left(3 \times 5^2 \div 15\right)-\left(5-2^2\right) \\
&=(3 \times 25 \div 15)-(5-4) \\
&=(3 \times 25 \div 15)-(5-4) \\
&=(75 \div 15)-(1) \\
&=(75 \div 15)-(1) \\
&=5-1 \\
&=4
\end{aligned}
\)
\(
\left(1^4 \times 2^2+3^3\right)-2^5 \div 4=?
\)
\(
\begin{aligned}
&\left(1^4 \times 2^2+3^3\right)-2^5 \div 4 \\
&=(1 \times 4+27)-32 \div 4 \\
&=(4+27)-32 \div 4 \\
&=(31)-32 \div 4 \\
&=31-8 \\
&=23
\end{aligned}
\)
\(
(22 \div 2-2 \cdot 5)^2+(4-6 \div 6)^2=?
\)
\(
\begin{aligned}
&(22 \div 2-2 \cdot 5)^2+(4-6 \div 6)^2 \\
&=(11-2 \cdot 5)^2+(4-1)^2 \\
&=(11-10)^2+(4-1)^2 \\
&=(1)^2+(3)^2 \\
&=1+9 \\
&=10
\end{aligned}
\)
\(
5+2^3 \times(22 \div 11)-3^2 \times(4+5)=?
\)
\(
\begin{aligned}
&5+2^3 \times(22 \div 11)-3^2 \times(4+5) \\
&=5+2^3 \times 2-3^2 \times 9 \\
&=5+8 \times 2-9 \times 9 \\
&=5+16-81 \\
&=21-81 \\
&=-60
\end{aligned}
\)
You cannot copy content of this page