Practice Corner MCQ

\(
\text { What does } \mathrm{A} \text { and } \mathrm{B} \text { represent in the given representation? }
\)

Sugar+Nitrogenous base =A

Phosphate group+sugar+nitrogenous base =B

A – Ribonucleoside, B – Deoxyribonucleoside
A – Ribonucleotide, B – Deoxyribonucleotide
A – Nucleoside, B – Nucleotide
A – Nucleotide, B – Nucleoside

In DNA strand, the nucleotides are linked together by

glycosidic bonds
phosphodiester bonds
peptide bonds
hydrogen bonds

In a DNA molecule, the phosphate group is attached to carbon \(\qquad\) of the sugar residue of its own nucleotide and carbon \(\qquad\) of the sugar residue of the next nucleotide by \(\qquad\) bonds.

\(5^{\prime}, 3^{\prime}\), phosphodiester
\(3^{\prime}, 5^{\prime}\), phosphodiester
5', 3', glycosidic
\(3^{\prime}, 5^{\prime}\), glycosidic

DNA as an acidic substance present in nucleus was first identified by \(\qquad\) in 1869; he named it as \(\qquad\)

Meischer, nuclein
Watson and Crick, DNA
Chargaff, nuclein
Wilkins and Franklin, double helix

Which of the following pairs is incorrectly matched?

Purines – Adenine and Guanine
Pyrimidines – Cytosine and Uracil
Nucleosides – Adenosine and Thymidine
DNA – Basic biomolecule

Watson and Crick (1953) proposed DNA double helix model and won the Nobel Prize; their model of DNA was based on
(i) X-ray diffraction studies of DNA done by Wilkins and Franklin
(ii) Chargaff’s base equivalence rule
(iii) Griffith’s transformation experiment
(iv) Meselson and Stahl’s experiment.

(i), (ii) and (iv)
(i) and (ii)
(iii) and (iv)
(i), (ii), (iii) and (iv)

If a double stranded DNA has \(20 \%\) of cytosine, what will be the percentage of adenine in it?

20 %
40 %
30 %
60 %

In one polynucleotide strand of a DNA molecule, the ratio of \(\mathrm{A}+\mathrm{T} / \mathrm{G}+\mathrm{C}\) is 0.3 . What is the \(\mathrm{A}+\mathrm{G} / \mathrm{T}+\mathrm{C}\) ratio of the entire DNA molecule?

0.3
0.6
1.2
1

If the sequence of bases in one strand of DNA is ATGCATGCA, what would be the sequence of bases on complementary strand?

ATGCATGCA
AUGCAUGCA
TACGTACGT
UACGUACGU

Refer to the given figure.

Select the option which correctly identifies K,L M and N.

a
b
c
d

The given flow chart represents the flow of genetic information between biomolecules. Identify the processes A, B, C and D and select the correct option.

A – Replication, B – Reverse Transcription, C – Transcription, D – Translation
A – Replication, B – Transcription, C – Reverse Transcription, D – Translation
A – Replication, B – Transcription, C – Translation, D – Reverse Transcription
A – Translation, B – Transcription, C- Replication, D – Reverse Transcription

Synthesis of DNA from RNA is explained by

central dogma reverse
reverse transcription
teminism
all of these

Histone proteins are

basic, negatively charged
basic, positively charged
acidic, positively charged
acidic, negatively charged

What does the given diagram represent?

Nucleosome
Spliceosome
Histone complex
Both (a) and (b)

The structure in chromatin seen as ‘beads-on string’ when viewed under electron microscope are called

nucleotides
nucleosides
histone octamer
nucleosomes

Refer the given figure of nucleosome and select the option that correctly identifies the parts A, B and C .

A-DNA B-Histone octamer C-\(H_1\) histone
A-Histone octamer B-\(H_1\) histone C-DNA
A-Histone octamer B-DNA C-\(H_1\) histone
A-DNA B-\(H_1\) histone C-\(H_1\) histone octamer

Read the following statements and select the correct option.
(i) Loosely packed and lightly stained region of chromatin are called as heterochromatin.
(ii) Densely packed and dark stained region of chromatin are called as euchromatin.
(iii) A typical nucleosome contains 200 bp of DNA helix.

Statements (i) and (ii) are true, but statement (iii) is false.
Statements (i) and (ii) are false, but statement (iii) is true.
Statements (ii) and (iii) are true, but statement (i) is false.
All the statements are true.

Other than DNA polymerase, which of the following enzymes is involved in DNA synthesis?

Topoisomerase
Helicase
RNA primase
All of these

Refer to the given steps of DNA replication.
(i) Exposure of DNA strands
(ii) Synthesis of RNA primer
(iii) Activation of deoxyribonucleotides
(iv) Chain formation
(v) Base pairing
(vi) Proof reading and DNA repair
(vii) DNA polymerase attaches at Ori site

Select the correct sequence of DNA replication.

(vii) \(\rightarrow\) (iii) \(\rightarrow\) (i) \(\rightarrow\) (ii) \(\rightarrow\) (v) \(\rightarrow\) (iv) \(\rightarrow\) (vi)
(iii) \(\rightarrow\) (i) \(\rightarrow\) (vii) \(\rightarrow\) (ii) \(\rightarrow\) (v) \(\rightarrow\) (iv) \(\rightarrow\) (vi)
(vii) \(\rightarrow\) (i) \(\rightarrow\) (iii) \(\rightarrow\) (ii) \(\rightarrow\) (v) \(\rightarrow\) (iv) \(\rightarrow\) (vi)
(i) \(\rightarrow\) (iii) \(\rightarrow\) (ii) \(\rightarrow\) (vii) \(\rightarrow\) (v) \(\rightarrow\) (iv) \(\rightarrow\) (vi)

Which of the following figures correctly represents the replication fork formed during DNA replication?

a
b
c
d

Select the incorrect statement regarding DNA replication.

Leading strand is formed in \(5^{\prime} \rightarrow 3^{\prime}\) direction.
Okazaki fragments are formed in \(5^{\prime} \rightarrow 3^{\prime}\) direction.
DNA polymerase catalyses polymerisation in \(5^{\prime} \rightarrow 3^{\prime}\) direction.
DNA polymerase catalyses polymerisation in \(3^{\prime} \rightarrow 5^{\prime}\) direction.

Which of the following differences are incorrect between leading and lagging strands of DNA?

\(
\begin{array}{|c|c|c|}
\hline & \text { Leading strand } & \text { Lagging strand } \\
\hline \text { (i) } & \begin{array}{l}
\text { It does not require } \\
\text { DNA ligase for its } \\
\text { growth. }
\end{array} & \begin{array}{l}
\text { DNA ligase is required } \\
\text { for joining Okazaki } \\
\text { fragments. }
\end{array} \\
\hline \text { (ii) } & \begin{array}{l}
\text { Formation of leading }
\end{array} & \begin{array}{l}
\text { Formation of lagging } \\
\text { strand is quite rapid. }
\end{array} \\
\hline
\end{array}
\)

\(
\begin{array}{|c|c|c|}
\hline \text { (iii) } & \begin{array}{l}
\text { Its template opens in } \\
5^{\prime} \rightarrow 3^{\prime} \text { direction. }
\end{array} & \begin{array}{l}
\text { Its template opens in } \\
3^{\prime} \rightarrow 5^{\prime} \text { direction. }
\end{array} \\
\hline \text { (iv) } & \begin{array}{l}
\text { Formation of leading } \\
\text { strand begins } \\
\text { immediately at } \\
\text { the beginning of }
\end{array} & \begin{array}{l}
\text { Formation of lagging } \\
\text { strand begins a bit later } \\
\text { than that of leading } \\
\text { strand. }
\end{array} \\
\hline
\end{array}
\)

(ii) and (iv) only
(ii), (iii) and (iv) only
(ii) and (iii) only
(i), (ii) and (iii) only

DNA replication takes place at \(\qquad\) phase of the cell cycle.

\(\mathrm{G}_1\)
\(S\)
\(\mathrm{G}_2\)
M

The process of copying genetic information from one strand of DNA into RNA is termed as \(\qquad\) –

replication
transcription
translation
reverse transcription

The given flow chart shows central dogma reverse

Enzymes used in processes A, B and C are respectively

A – DNA dependent DNA polymerase, B – RNA dependent DNA polymerase, C- DNA dependent RNA polymerase
A – DNA dependent DNA polymerase, B – DNA dependent RNA polymerase, C – RNA dependent DNA polymerase
A – DNA dependent RNA polymerase, B – DNA dependent DNA polymerase, C – RNA dependent DNA polymerase
A – RNA dependent DNA polymerase, B – DNA dependent RNA polymerase, C – RNA dependent RNA polymerase.

The enzyme DNA dependent RNA polymerase catalyses the polymerisation reaction in \(\qquad\) direction.

only \(5^{\prime} \rightarrow 3^{\prime}\)
only \(3^{\prime} \rightarrow 5^{\prime}\)
both (a) and (b)
none of these

What would be the base sequence of RNA transcript obtained from the given DNA segment?
\(5^{\prime}\) – G CATT C G G CTA G TAA C \(-3^{\prime}\) Coding strand of DNA
\(3^{\prime}\) – C GTAAGCCGATCATTG – \(5^{\prime}\) Non-coding strand of DNA

\(5^{\prime}-G C A \cup \cup C G G C \cup A G \cup A A C-3^{\prime}\)
\(5^{\prime}-C G \cup A A G C C G A \cup C A \cup \cup G-3^{\prime}\)
\(5^{\prime}\) – GCATTCGGCTAGTAAC \(-3^{\prime}\)
\(3^{\prime}-\) CGTAAGCCGATCATTG-5

If the sequence of bases in coding strand of DNA is ATTCGATG, then the sequence of bases in mRNA will be

TAAGCTAC
UAAGCUAC
ATTCGATG
AUUCGAUG

If the sequence of bases in DNA is GCTTAGGCAA, then the sequence of bases in its transcript will be

GCTTAGGCAA
CGAATCCGIT
CGAAUCCGUU
AACGGAUUCG

Given diagram represents the components of a transcription unit. Select the correct answer regarding it.

A Terminator, B Promoter, C – Template strand, D – Coding strand
A Promoter, B Terminator, C – Coding strand, D – Template strand
A Promoter, B Terminator, C – Template strand, D – Coding strand
A Terminator, B Promoter, C – Coding strand, D – Template strand

Transcription unit

starts with TATA box
starts with palindrome regions and ends with rho factor
starts with promoter region and ends in terminator region
starts with CAAT region

During transcription, the site of DNA molecule at which RNA polymerase binds is called

promoter
regulator
receptor
enhancer

Select the correct match of enzyme with its related function.

DNA polymerase – Synthesis of DNA strands
Helicase – Unwinding of DNA helix
Ligase – Joins short DNA segments together
All of these

Polycistronic messenger RNA (mRNA) usually occurs in

bacteria
prokaryotes
eukaryotes
both (a) and (b)

The given figure represents the process of transcription in bacteria.

Select the option which correctly labels A, B and C.

A – DNA, B – RNA, C – Rho factor
A – RNA, B – RNA polymerase, C – Rho factor
A – RNA, B – RNA polymerase, C – Sigma factor
A – DNA, B – DNA polymerase, C – Sigma factor

Refer to the given diagram. What does it represent?

Transcription in prokaryotes
Transcription in eukaryotes
Translation in prokaryotes
Translation in eukaryotes

In transcription in eukaryotes, heterogenous nuclear RNA (hnRNA) is transcribed by

RNA polymerase I
RNA polymerase II
RNA polymerase III
all of these

Methyl guanosine triphosphate is added to the \(5^{\prime}\) end of hnRNA in a process of

splicing
capping
tailing
none of these

Select the correct statements regarding the process of transcription in eukaryotes.
(i) The strand of dsDNA which takes part in transcription process is called as coding strand.
(ii) The enzyme RNA polymerase can catalyse polymerisation only in one direction i.e., \(5^{\prime} \rightarrow 3^{\prime}\).
(iii) An unusual nucleotide methyl guanosine triphosphate is added to the \(5^{\prime}\) end of hnRNA during capping.
(iv) During tailing process, adenylate residues (200300) are added at \(3^{\prime}\) end in a template independent manner.

(i) and (ii)
(iii) and (iv)
(ii), (iii) and (iv)
(i), (ii), (iii) and (iv)

In eukaryotes, the process of processing of primary transcript involves

removal of introns
capping at \(5^{\prime}\) end
tailing (polyadenylation) at 3' end
all of these

Match column I with column II and select the correct option from the given codes

\(
\begin{array}{|c|l|c|l|}
\hline & \text { Column I } & & \text { Column II } \\
\hline \text { A. } & \text { Sigma factor } & \text { (i) } & 5^{\prime}-3^{\prime} \\
\hline \text { B. } & \text { Capping } & \text { (ii) } & \text { Initiation } \\
\hline \text { C. } & \text { Tailing } & \text { (iii) } & \text { Termination } \\
\hline \text { D. } & \text { Coding strand } & \text { (iv) } & 5^{\prime} \text { end } \\
\hline & & \text { (v) } & 3^{\prime} \text { end } \\
\hline
\end{array}
\)

A-(iii), B-(v), C-(iv), D-(ii)
A-(ii), B-(iv), C-(v), D-(i)
A-(ii), B-(iv), C-(v), D-(iii)
A-(iii), B-(v), C-(iv), D-(i)

Identify A, B, C and D in the given diagram of m R N A.

A – Methylated cap B – Initiation codon C – Termination codon D – Poly A tail
A – Poly A tail B – Termination codon C – Initiation codon D – Methylated cap
A – Methylated cap B – Non-coding region C – Coding region D – Poly A tail
A – Methylated cap B – Coding region C – Non-coding region D – Poly A tail

The fully processed hnRNA is called as (i) and is transported out of the (ii) into the (iii) for translation.

(i) mRNA, (ii) Nucleus, (iii) Cytoplasm
(i) tRNA, (ii) Nucleus, (iii) Cytoplasm
(i) mRNA, (ii) Cytoplasm, (iii) Nucleus
(i) tRNA, (ii) Cytoplasm, (iii) Nucleus

Refer to the given sequence of steps and select the correct option.

(i) Replication, (ii) Processing, (iii) – Translation
(i) Replication, (ii) Transcription, (iii) – Translation
(i) Transcription, (ii) Splicing, (iii) – Translation
(i) Transcription, (ii) Replication, (iii) – Translation

The three codons which result in the termination of polypeptide chain synthesis are

UAA, UAG, GUA
UAA, UAG, UGA
UAA, UGA, UUA
UGU, UAG, UGA

Match column I with column II and select the correct option from the given codes.

\(
\begin{array}{|c|l|c|l|}
\hline & \begin{array}{l}
\text { Column I } \\
\text { (Codons) }
\end{array} & & \begin{array}{l}
\text { Column II } \\
\text { (Translated amino acid) }
\end{array} \\
\hline \text { A. } & \text { UUU } & \text { (i) } & \text { Serine } \\
\hline \text { B. } & \text { GGG } & \text { (ii) } & \text { Methionine } \\
\hline \text { C. } & \text { UCU } & \text { (iii) } & \text { Phenylalanine } \\
\hline \text { D. } & \text { CCC } & \text { (iv) } & \text { Glycine } \\
\hline \text { E. } & \text { AUG } & \text { (v) } & \text { Proline } \\
\hline
\end{array}
\)

A-(iii), B-(iv), C-(i), D-(v), E-(ii)
A-(iii), B-(i), C-(iv), D-(v), E-(ii)
A-(iii), B-(iv), C-(v), D-(i), E-(ii)
A-(ii), B-(iv), C-(i), D-(v), E-(iii)

Amino acids which are specified by single codons are

phenylalanine and arginine
tryptophan and methionine
valine and proline
methionine and arginine

Which out of the following statements is incorrect?

Genetic code is ambiguous.
Genetic code is degenerate.
Genetic code is universal.
Genetic code is non-overlapping.

Some amino acids are coded by more than one codon, hence the genetic code is

overlapping
degenerate
wobbled
unambiguous

Read the following statements.
(i) One codon codes for only one amino acid.
(ii) Some amino acids are coded by more than one codon
(iii) The sequence of triplet nitrogenous bases in DNA or mRNA corresponds to the amino acid sequence in the polypeptide chain.

Give suitable terms for the characteristics of ‘genetic code’ as per the above statements.

Degeneracy (i) Colinearity (iii) Uambiguous (ii)
Degeneracy (iii) Colinearity (ii) Uambiguous (i)
Degeneracy (ii) Colinearity (iii) Uambiguous (i)
Degeneracy (i) Colinearity (ii) Uambiguous (iii)

The mutations that involve addition, deletion or substitution of a single base pair in a gene are referred to as

point mutations
lethal mutations
silent mutations
retrogressive mutations

Sickle cell anemia results from a single base substitution in a gene, thus it is an example of

point mutation
frame-shift mutation
silent mutation
both (a) and (b)

Select the incorrectly matched pair.

Initiation codons – AUG, GUG
Stop codons – UAA, UAG, UGA
Methionine – AUG
Anticodons – mRNA

Identify the labels A, B, C and D in the given structure of tRNA and select the correct option.

a
b
c
d

The differences between mRNA and tRNA are that
(i) mRNA has more elaborated 3-dimensional structure due to extensive base-pairing
(ii) tRNA has more elaborated 3-dimensional structure due to extensive base-pairing
(iii) tRNA is usually smaller than mRNA
(iv) mRNA bears anticodon but tRNA has codons.

(i) and (ii)
(ii) and (iii)
(i), (ii) and (iii)
(i), (ii), (iii) and (iv)

Amino acid acceptor end of tRNA lies at

\(5^{\prime}\) end
3' end
\(T \Psi C\) loop
DHU loop

Which RNA carries the amino acids from the amino acid pool to mRNA during protein synthesis?

rRNA
mRNA
tRNA
hnRNA

During translation, activated amino acids get linked to tRNA. This process is commonly called as

charging of \(t\) RNA
discharging of \(t\) RNA
aminoacylation of \(t\) RNA
both (a) and (c)

Refer to the given mRNA segment which can be translated completely into a polypeptide.

Which of the following codons may correspond with \(A\) and \(B\) ?

\(A\) – AUG, GUG; B – UAA, UAG or UGA
A – UAA, UGA; B – AUG, GUG or UAG
A – AUG, UGA; B – GUG, UAA or UGA
A – AUG, GAG; B – UAA, UUU or UGA

In a mRNA molecule, untranslated regions (UTRs) are present at

5' – end (before start codon)
\(3^{\prime}\) – end (after stop codon)
both (a) and (b)
3' – end only

UTRs are the untranslated regions present on

rRNA
tRNA
mRNA
hnRNA

Given below are the steps of protein synthesis. Arrange them in correct sequence and select the correct option.
(i) Codon-anticodon reaction between mRNA and aminoacyl tRNA complex
(ii) Attachment of mRNA and smaller sub-unit of ribosome
(iii) Charging or aminoacylation of tRNA
(iv) Attachment of larger sub-unit of ribosome to the mRNA-tRNA \({ }_{\text {Met }}\) complex
(v) Linking of adjacent amino acids.
(vi) Formation of polypeptide chain.

(ii) \(\rightarrow\) (i) \(\rightarrow\) (iii) \(\rightarrow\) (v) \(\rightarrow\) (iv) \(\rightarrow\) (vi)
(v) \(\rightarrow\) (ii) \(\rightarrow\) (i) \(\rightarrow\) (iii) \(\rightarrow\) (iv) \(\rightarrow\) (vi)
(iii) \(\rightarrow\) (ii) \(\rightarrow\) (iv) \(\rightarrow\) (i) \(\rightarrow\) (v) \(\rightarrow\) (vi)
(iii) \(\rightarrow\) (ii) \(\rightarrow\) (i) \(\rightarrow\) (iv) \(\rightarrow\) (v) \(\rightarrow\) (vi)

Refer to the given figure.

Select the option which identifies polarity X and Y and DNA sequence coding for serine P and the anticodon for the same amino acid (Q).

a
b
c
d

Which of the following statements is correct regarding ribosomes?

Most of a cell's DNA molecule are stored there.
Complete polypeptide is released from there.
\(m\) RNAs are produced there.
DNA replication takes place there.

What would happen if in a gene encoding a polypeptide of 50 amino acids, \(25^{\text {th }}\) codon (UAU) is mutated to UAA?

A polypeptide of 24 amino acids will be formed.
Two polypeptides of 24 and 25 amino acids will be formed.
A polypeptide of 49 amino acids will be formed.
A polypeptide of 25 amino acids will be formed.

Match column I with column II and select the correct option from the given codes.

A-(ii), B-(i), C-(iii)
A-(i), B-(iii), C-(ii)
A-(iii), B-(i), C-(ii)
A-(ii), B-(iii), C-(i)

Regulation of gene expression occurs at the level of

transcription
processing/splicing
translation
all of these

During expression of an operon, RNA polymerase binds to

structural gene
regulator gene
operator
promoter

The sequence of structural genes in lac operon is

lac a, lac y, lac \(z\)
lac a, lac \(z_1\) lac \(y\)
lac y, lac z, lac a
lac z, lac y, lac a

Match column I with column II and select the correct option from the given codes.

\(
\begin{array}{|c|c|c|c|}
\hline & \text { Column I } & & \text { Column II } \\
\hline \text { A. } & \text { Operator site } & \text { (i) } & \begin{array}{l}
\text { Binding site for RNA } \\
\text { polymerase }
\end{array} \\
\hline \text { B. } & \text { Pro } & \text { (ii) } & \begin{array}{l}
\text { Binding site for repressor } \\
\text { molecule }
\end{array} \\
\hline \text { C. } & \text { Regulator gene } & \text { (iii) } & \text { Codes for protein / enzyme } \\
\hline \text { D. } & \text { Structural gene } & \text { (iv) } & \begin{array}{l}
\text { Codes for repressor } \\
\text { molecule }
\end{array} \\
\hline
\end{array}
\)

A – (ii), B – (i), C – (iii), D – (iv)
A – (ii), B – (i), C – (iv), D – (iii)
A- (iv), B – (iii), C – (i), D – (ii)
A – (ii), B – (iii), C – (i), D – (iv)

Which of the following cannot act as inducer?

Glucose
Lactose
Galactose
Both (a) and (c)

Inducible operon system usually occurs in (i) pathways. Nutrient molecules serve as (ii) to stimulate production of the enzymes necessary for their breakdown. Genes for inducible operon are usually switched (iii) and the repressor is synthesised in an (iv) form.

(i) catabolic (ii) inducer (iii) off (iv) active
(i) catabolic (ii) corepressor (iii) on, (iv) inactive
(i) anabolic (ii) inducer (iii) off (iv) active
(i) anabolic (ii) corepressor (iii) on (iv) inactive

Repressible operon system is usually found in (i) pathways. The pathway’s end product serves as a (ii) to activate the repressor, turn off enzyme synthesis and prevent overproduction of the end product of the pathway. Genes for this operon are usually switched (iii) and the repressor is synthesised in an (iv) form.

(i) anabolic (ii) corepressor (iii) on (iv) inactive
(i) anabolic (ii) inducer (iii) off (iv) active
(i) catabolic (ii) inducer (iii) off (iv) active
(i) catabolic (ii) corepressor (iii) on (iv) inactive

Match column I with column II and select the correct option from the given codes.

\(
\begin{array}{|l|l|l|l|}
\hline & \text { Column I } & & \text { Column II } \\
\hline \text { A. } & \text { Griffith } & \text { (i) } & \text { Lac operon } \\
\hline \text { B. } & \text { Hershey and Chase } & \text { (ii) } & \begin{array}{l}
\text { Semi-conservative } \\
\text { DNA replication }
\end{array} \\
\hline
\end{array}
\)

A-(iv), B-(iii), C-(ii), D-(i)
A-(iii), B-(iv), C-(ii), D-(i)
A-(iv), B-(ii), C-(iii), D-(i)
A-(ii), B-(i), C-(iii), D-(iv)

Human genome consists of approximately

\(3 \times 10^9 \mathrm{bp}\)
\(6 \times 10^9 \mathrm{bp}\)
20,000-25,000 bp
\(2.2 \times 10^4 \mathrm{bp}\)

Estimated number of genes in human beings is

3,000
80,000
20,500.
\(3 \times 10^9\)

Which of the following statements regarding ‘human genome’ is incorrect?

Human genome consists of \(3 \times 10^9 \mathrm{bp}\) and about 20,500 genes.
The average gene size is 3000 bp and dystrophin is the largest known human gene.
Chromosome 1 contains maximum (2968) number of genes and Y-chromosome has the least (231) number of genes.
Repeated (or repetitive) sequences are not present in human genome.

Select the correct option that correctly fill the blanks (i) – (iv).
I. Less than (i) of genome represents structural genes that code for proteins.
II. Chemical substance that binds with repressor and convert it into a non-DNA binding state is (ii).
III. In prokaryotes, during replication RNA primer is removed by (iii) whereas in eukaryotes it is removed by (iv).

(i) 5% (ii) regulator (iii) DNA polymerase II (iv) DNA polymerase B
(i) 10% (ii) regulator (iii) DNA polymerase I (iv) DNA polymerase a
(i) 2% (ii) inducer (iii) DNA polymerase I (iv) DNA polymerase B
(i) 50% (ii) inducer (iii) DNA polymerase III (iv) DNA polymerase a

Arrange the various steps of DNA fingerprinting technique in the correct order.
(i) Separation of DNA fragments by electrophoresis.
(ii) Digestion of DNA by restriction endonucleases.
(iii) Hybridisation using labelled VNTR probe.
(iv) Isolation of DNA.
(v) Detection of hybridised DNA fragments by autoradiography.
(vi) Transferring the separated DNA fragments to nitrocellulose membrane.

(iv) \(\rightarrow\) (ii) \(\rightarrow\) (i) \(\rightarrow\) (vi) \(\rightarrow\) (iii) \(\rightarrow\) (v)
(iv) \(\rightarrow\) (i) \(\rightarrow\) (ii) \(\rightarrow\) (iii) \(\rightarrow\) (vi) \(\rightarrow\) (v)
(ii) \(\rightarrow\) (i) \(\rightarrow\) (iv) \(\rightarrow\) (vi) \(\rightarrow\) (iii) \(\rightarrow\) (v)
(iii) \(\rightarrow\) (v) \(\rightarrow\) (iv) \(\rightarrow\) (ii) \(\rightarrow\) (i) \(\rightarrow\) (vi)

CLASS-XII BIOLOGY + NEET

Practice Corner MCQ

Quiz Summary

Information

Results

Results

Categories

1. Question

Hint

2. Question

Hint

3. Question

Hint

4. Question

Hint

5. Question

Hint

6. Question

Hint

7. Question

Hint

8. Question

Hint

9. Question

Hint

10. Question

Hint

11. Question

Hint

12. Question

Hint

13. Question

Hint

14. Question

Hint

15. Question

Hint

16. Question

Hint

17. Question

Hint

18. Question

Hint

19. Question

Hint

20. Question

Hint

21. Question

Hint

22. Question

Hint

23. Question

Hint

24. Question

Hint

25. Question

Hint

26. Question

Hint

27. Question

Hint

28. Question

Hint

29. Question

Hint

30. Question

Hint

31. Question

Hint

32. Question

Hint

33. Question

Hint

34. Question

Hint

35. Question

Hint

36. Question

Hint